Template:Fac Ratio
Syntax: {{Fac Ratio|fac|1stnum|1stfac|2ndnum|2ndfac|3rdnum|3rdfac|4thnum|4thfac|5thfac|5thfac|ratio={TABLE}|fully={facs}|fullynum={facnum}}}
Example: {{Fac Ratio|Steel mill|4/7|Coal mine|1/7|Iron mine|ratio={{{!}}
<br>{{!}} 1 [[Iron mine]] : 1 [[Coal mine]] : 1 [[Steel mill]] at minimun
<br>{{!}}-
<br>{{!}} 4 [[Iron mine]] : 7 [[Steel mill]]
<br>{{!}}-
<br>{{!}} 1 [[Coal mine]] : 7 [[Steel mill]]
<br>{{!}}}
<br>|fully=4 [[Coal mine]] and 1 [[Iron mine]]|fullynum=7}}
gives
You need 4/7 of 1 Coal mine, 1/7 of 1 Iron mine to maintain this factory. In other words, You need 4 Coal mine and 1 Iron mine for 7 Steel mill to create fully passive production line without excessive input.
| 1 Iron mine : 1 Coal mine : 1 Steel mill at minimun |
| 4 Iron mine : 7 Steel mill |
| 1 Coal mine : 7 Steel mill |
Disclaimer: The ratio above is only for calculation only. The real value may vary.
