Difference between revisions of "Template:Fac Ratio"
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| − | You need {{#if: {{{3|}}}|{{{2}}} of 1 [[{{{3}}}]]|'''Empty'''}}{{#if: {{{5|}}}|, {{{4}}} of 1 [[{{{5}}}]]}}{{#if: {{{7|}}}|, {{{6}}} of 1 [[{{{7}}}]]}}{{#if: {{{9|}}}|, {{{8}}} of 1 [[{{{9}}}]]}}{{#if: {{{11|}}}|, {{{10}}} of 1 [[{{{11}}}]]}} to maintain this factory. | + | You need {{#if: {{{3|}}}|{{{2}}} of 1 [[{{{3}}}]]|'''Empty'''}}{{#if: {{{5|}}}|, {{{4}}} of 1 [[{{{5}}}]]}}{{#if: {{{7|}}}|, {{{6}}} of 1 [[{{{7}}}]]}}{{#if: {{{9|}}}|, {{{8}}} of 1 [[{{{9}}}]]}}{{#if: {{{11|}}}|, {{{10}}} of 1 [[{{{11}}}]]}} to maintain this factory.<br>To become fewer remains and a perfect production, you will need {{{fully}}} for {{{fullynum}}} [[{{{1}}}]] but remember it may vary.. |
{{{ratio}}} | {{{ratio}}} | ||
Revision as of 16:50, 3 July 2021
Syntax: {{Fac Ratio|fac|1stnum|1stfac|2ndnum|2ndfac|3rdnum|3rdfac|4thnum|4thfac|5thfac|5thfac|ratio={TABLE}|fully={facs}|fullynum={facnum}}}
Example: {{Fac Ratio|Steel mill|4/7|Coal mine|1/7|Iron mine|ratio={|
| 1 Iron mine : 1 Coal mine : 1 Steel mill at minimun
|-
| 4 Iron mine : 7 Steel mill
|-
| 1 Coal mine : 7 Steel mill
|}
|fully=4 Coal mine and 1 Iron mine|fullynum=7}}
gives
You need 4/7 of 1 Coal mine, 1/7 of 1 Iron mine to maintain this factory.
To become fewer remains and a perfect production, you will need 4 Coal mine and 1 Iron mine for 7 Steel mill but remember it may vary..
| 1 Iron mine : 1 Coal mine : 1 Steel mill at minimun |
| 4 Iron mine : 7 Steel mill |
| 1 Coal mine : 7 Steel mill |
Disclaimer: The ratio above is only for calculation only. The real value may vary.
